How do you simplify #(7+8/2+1)(5-5)# using order of operations?

1 Answer
Oct 1, 2016

Answer:

The value of this expression is zero (0).

Explanation:

If there is more than one expression in brackets, then the values can be calculated in any order.

Note also that if one of the factors is zero, then the whole product is also zero (no matter what the other factor is).

Now we can calculate that:

#(7+8/2+1)xx(5-5)=(7+8/2+1)xx0=0#