How do you simplify #7/8 div 3/4#?

2 Answers
Aug 24, 2016

Answer:

#7/6#

Explanation:

To make the division into a multiplication question, which are the easiest to solve, all you do is flip the right-hand fraction upside down and change the divide to a multiply. So it becomes:

#7/8 times 4/3#

Cancel the 4 on the top with the eight on the bottom and you are left with:

#7/cancel8^2 times cancel4/3 rarr 7/2 times 1/3#

Multiply the top numbers together and the bottom numbers together, and you get the final answer:

#7/6#

Answer:

Write the equation as a complex fraction. and then simply the problem.

Explanation:

#7/8# is a division, it means 7 divided by 8.

#3/4# is a division, it means 3 divided by 4

#7/8# divided by #3/4# can be written as one division.
#(7/8)/(3/4)#

Now use the multiplicative inverse to make the bottom fraction (the denominator) #3/4# disappear

Multiply both the bottom fraction (denominator) and the top fraction(#7/8#) (numerator) by the multiplicative inverse #4/3#

# (7/8) xx (4/3) / (3/4 xx 4/3) #

# (3/4) xx (4/3)# = 1

leaving #(7/8) xx (4/3) = 28/ 24 = 7/6 = 1 1/6#