How do you simplify #(7-9+2) div ((-4)^2 + (-6)^3)# using PEMDAS?

1 Answer
Jul 20, 2016

Answer:

0

Explanation:

This is all one term, but it is made up of different parts.

Start from inside the parentheses

#(7-9+2) div ((-4)^2 + (-6)^3)#

=#(0) div ((-4)^2 + (-6)^3)#

As the first part is equal to 0, there is no need to continue, because

#0/((-4)^2 + (-6)^3) = 0#