How do you simplify #7 log_3 k + 6 log_3 m – 9 log_3 n#?

1 Answer
Jun 25, 2015

Answer:

Adding logs (with the same ground number) is like multiplying the arguments.

Explanation:

And subtraction boils down to division.

But first we must get the coefficients behind the log, remembering that #n*log x=log x^n#

#=log_3 k^7+log_3 m^6-log_3 n^9#

Since they are all #log_3# we may then multiply and divide the arguments:

#=log_3((k^7*m^6)/n^9)#