Question

How do you simplify `7 log_3 k + 6 log_3 m – 9 log_3 n`?

Answer 1

Adding logs (with the same ground number) is like multiplying the arguments.

Explanation:

And subtraction boils down to division.

But first we must get the coefficients behind the log, remembering that `n*log x=log x^n`

`=log_3 k^7+log_3 m^6-log_3 n^9`

Since they are all `log_3` we may then multiply and divide the arguments:

`=log_3((k^7*m^6)/n^9)`