# How do you simplify (-7c^3d^4)(4cd^3)?

Feb 9, 2017

See the entire simplification process below:

#### Explanation:

First, rewrite the equation to group like terms:

$\left(- 7 \times 4\right) \left({c}^{3} \times c\right) \left({d}^{4} \times {d}^{3}\right)$

Use the two rules of exponents to complete the simplification:

$a = {a}^{\textcolor{red}{1}}$

${x}^{\textcolor{red}{a}} \times {x}^{\textcolor{b l u e}{b}} = {x}^{\textcolor{red}{a} + \textcolor{b l u e}{b}}$

$\left(- 7 \times 4\right) \left({c}^{3} \times {c}^{\textcolor{b l u e}{1}}\right) \left({d}^{4} \times {d}^{3}\right) \to$

$- 28 {c}^{3 + 1} {d}^{4 + 3} \to$

$- 28 {c}^{4} {d}^{7}$