How do you simplify (7w^11z^6)/(14w^3z^3)?

Jun 27, 2017

See a solution process below:

Explanation:

First, rewrite the expression as:

$\left(\frac{7}{14}\right) \left({w}^{11} / {w}^{3}\right) \left({z}^{6} / {z}^{3}\right) \implies \frac{1}{2} \left({w}^{11} / {w}^{3}\right) \left({z}^{6} / {z}^{3}\right)$

Now, use this rule of exponents to simplify the $w$ and $z$ terms:

${x}^{\textcolor{red}{a}} / {x}^{\textcolor{b l u e}{b}} = {x}^{\textcolor{red}{a} - \textcolor{b l u e}{b}}$

$\frac{1}{2} \left({w}^{\textcolor{red}{11}} / {w}^{\textcolor{b l u e}{3}}\right) \left({z}^{\textcolor{red}{6}} / {z}^{\textcolor{b l u e}{3}}\right) \implies \frac{1}{2} \left({w}^{\textcolor{red}{11} - \textcolor{b l u e}{3}}\right) \left({z}^{\textcolor{red}{6} - \textcolor{b l u e}{3}}\right) \implies$

$\frac{{w}^{8} {z}^{3}}{2}$