# How do you simplify 7x^3y^8(-4x^2y^4)?

$- 28 {x}^{5} {y}^{12}$
$7 {x}^{3} {y}^{8} \left(- 4 {x}^{2} {y}^{4}\right) = - 28 {x}^{3 + 2} {y}^{8 + 4} = - 28 {x}^{5} {y}^{12}$