How do you simplify #(8 – (4 – 2) )* ( 4+(8 + 6) ) #? Algebra Expressions, Equations, and Functions PEMDAS 1 Answer Veddesh #phi# Feb 3, 2016 #(8-(4-2))*(4+(8+6))# We can first solve the first bracket: #rarr(8-(2))*(4+(8+6))# #rarr(6)*(4+(8+6))# #rarr(6)*(4+(14))# #rarr(6)*(18)=108# Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #(4-2)^3-4*8+21div3#? See all questions in PEMDAS Impact of this question 1564 views around the world You can reuse this answer Creative Commons License