# How do you simplify 8a^5 d^-5?

Since, in general, ${b}^{- p} = \frac{1}{b} ^ p$
$8 {a}^{5} {d}^{- 5} = 8 {a}^{5} / {d}^{5} = 8 {\left(\frac{a}{d}\right)}^{5}$