# How do you simplify 8x^-3y^3 and write it using only positive exponents?

Dec 21, 2016

$\frac{8 {y}^{3}}{{x}^{3}}$
${x}^{-} 3 = \frac{1}{x \times x \times x}$ The negative exponent means to divide.
so $\frac{1}{x \times x \times x}$ = $\frac{1}{x} ^ 3$