# How do you simplify (8x - 8)/(x^2 + x - 2)?

$\frac{8 x - 8}{{x}^{2} + x - 2}$
$= \frac{8 \left(\cancel{x - 1}\right)}{\left(x + 2\right) \left(\cancel{x - 1}\right)}$
$= \frac{8}{x + 2}$