# How do you simplify 8z(2z^2-15)?

May 21, 2018

$16 {z}^{3} - 120 z$

#### Explanation:

I assume since this is a distributive property question:

$8 z \left(2 {z}^{2} - 15\right)$

$16 {z}^{3} - 120 z$

Whether that form is simpler or not remains to be debated :-)