How do you simplify #(9 1/3+4 1/3)div 6-(-12)#?

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Answer 1 · 2018-04-30T21:25:25

#14 5/18#

Count the number of terms first and simplify each term separately.

#color(blue)((9 1/3 + 4 1/3) div 6)" "color(red)( - (-12))#

#=color(blue)((13 2/3) div 6)" "color(red)( +12)#

#=color(blue)(41/3 xx 1/6)" "color(red)( +12)#

#=color(blue)(41/18)" "color(red)( +12)#

#=color(blue)(2 5/18)" "color(red)( +12)#

#= 14 5/18#