How do you simplify #(9 1/3+4 1/3)div 6-(-12)#?

1 Answer
Apr 30, 2018

Answer:

#14 5/18#

Explanation:

Count the number of terms first and simplify each term separately.

#color(blue)((9 1/3 + 4 1/3) div 6)" "color(red)( - (-12))#

#=color(blue)((13 2/3) div 6)" "color(red)( +12)#

#=color(blue)(41/3 xx 1/6)" "color(red)( +12)#

#=color(blue)(41/18)" "color(red)( +12)#

#=color(blue)(2 5/18)" "color(red)( +12)#

#= 14 5/18#