# How do you simplify 9^(log_9x)?

${9}^{{\log}_{9} x} = x$
Let ${9}^{{\log}_{9} x} = u$, then as ${a}^{n} = b$ means ${\log}_{a} b = n$, we have
${\log}_{9} u = {\log}_{9} x$.
Hence $u = x$ and ${9}^{{\log}_{9} x} = x$