# How do you simplify (9b^6 - 6b^3 + 2)/(3b^3)?

May 25, 2018

$3 {b}^{3} - 2 + \frac{2 {b}^{-} 3}{3}$

#### Explanation:

We can rewrite the expression as $\frac{9 {b}^{6} - 6 {b}^{3}}{3 {b}^{3}} + \frac{2}{3 {b}^{3}}$

We can factor the first fraction with $3 {b}^{3}$, and cancel.

$\frac{\cancel{3 {b}^{3}} \left(3 {b}^{3} - 2\right)}{\cancel{3 {b}^{3}}} = 3 {b}^{3} - 2$

$\frac{2}{3 {b}^{3}} = \frac{2}{3} \cdot {b}^{-} 3 = \frac{2 {b}^{-} 3}{3}$

$3 {b}^{3} - 2 + \frac{2 {b}^{-} 3}{3}$