How do you simplify #9sqrt2 + sqrt32#?

2 Answers
Feb 13, 2016

Answer:

I found #13sqrt(2)#

Explanation:

We can manipulate the second root and write:
#9sqrt(2)+sqrt(2*16)=#
#=9sqrt(2)+[sqrt(2)*sqrt(16)]=#
#=9sqrt(2)+4sqrt(2)=#
add:
#=13sqrt(2)#

Feb 13, 2016

Answer:

#13sqrt2 #

Explanation:

to begin , simplify # sqrt32 #

32 may be written as 16# xx 2#

when simplifying , look for factors which are 'squares' as 16 is.

hence #sqrt32 = sqrt(16 xx 2 ) = sqrt16 xxsqrt2 = 4sqrt2#

expression can now be written : # 9sqrt2 + 4sqrt2 = 13sqrt2 #