How do you simplify #(-9x)/(x-x^2)# and what are the restrictions?

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Answer 1 · 2015-06-06T20:08:10

You can write it as:
#(-9cancel(x))/(cancel(x)(1-x))=-9/(1-x)#
The restrictions are (to avoid a division by zero):
#x!=0#
#x!=1#