# How do you simplify 9y^4j^2y^-9?

Jul 17, 2016

$\textcolor{g r e e n}{\frac{9 {j}^{2}}{y} ^ 5}$

#### Explanation:

Note this law: ${a}^{-} b = \frac{1}{a} ^ b$

and this as well: ${a}^{b} / {a}^{c} = {a}^{b - c}$


$9 {y}^{4} {j}^{2} {y}^{-} 9$

Follow the first rule mentioned above and rewrite the expression:

$\frac{9 {y}^{4} {j}^{2}}{y} ^ - 9$

Now use the second law to simplify the $y$ terms in the numerator and denominator:

$9 {y}^{4 - 9} {j}^{2}$

$9 {y}^{-} 5 {j}^{2}$

Jump back to the first law and rewrite the negative exponent:

$\textcolor{g r e e n}{\frac{9 {j}^{2}}{y} ^ 5}$