How do you simplify (a^0-3b^0)^5?

Mar 28, 2018

${\left(- 2\right)}^{5} = - 32$

Explanation:

Given: ${\left({a}^{0} - 3 {b}^{0}\right)}^{5}$

We know that ${x}^{0} = 1 , x \setminus \in \mathbb{R} , x \ne 0$.

Therefore,

$= {\left(1 - 3 \cdot 1\right)}^{5}$

$= {\left(1 - 3\right)}^{5}$

$= {\left(- 2\right)}^{5}$

$= - 32$