How do you simplify #(a^-1b^2)/(ab) times (a^2b^3)/b^-2#? Algebra Exponents and Exponential Functions Exponential Properties Involving Quotients 1 Answer EZ as pi Sep 4, 2016 #b^6# Explanation: #(color(red)(a^-1)b^2)/(ab) times (a^2b^3)/color(blue)(b^-2)# Use the law of indices #x^-m = 1/x^m# to get rid of the negative indices. =#(b^2)/(color(red)(a)ab) xx (a^2b^3color(blue)(b^2 ))/1" "larr"now simplify"# =#(a^2b^7)/(a^2b)# =#b^6# Answer link Related questions What is the quotient of powers property? How do you simplify expressions using the quotient rule? What is the power of a quotient property? How do you evaluate the expression #(2^2/3^3)^3#? How do you simplify the expression #\frac{a^5b^4}{a^3b^2}#? How do you simplify #((a^3b^4)/(a^2b))^3# using the exponential properties? How do you simplify #\frac{(3ab)^2(4a^3b^4)^3}{(6a^2b)^4}#? Which exponential property do you use first to simplify #\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}#? How do you simplify #(x^5y^8)/(x^4y^2)#? How do you simplify #[(2^3 *-3^2) / (2^4 * 3^-2)]^2#? See all questions in Exponential Properties Involving Quotients Impact of this question 1787 views around the world You can reuse this answer Creative Commons License