# How do you simplify (a^4 b^-2 c^0)/(a b^4 c^-2)?

Mar 13, 2018

${a}^{3} {b}^{-} 6 {c}^{2}$

#### Explanation:

$\frac{{a}^{4} {b}^{-} 2 {c}^{0}}{a {b}^{4} {c}^{-} 2}$

You simplify in these situation by subtracting the powers, if that makes sense (e.g. ${a}^{5} / {a}^{3} = {a}^{5 - 3} = {a}^{2}$) So the above expression becomes:

a^(4-1)b^(-2-4)c^(0-(-2)

${a}^{3} {b}^{-} 6 {c}^{2}$