# How do you simplify #abs((-(3-1)+5)div(-2))#?

##### 2 Answers

#### Explanation:

The absolute value of a number is always positive, but before we can do the absolute value, we need to simplify what is inside of it. So let's do that:

The first thing I'm seeing is that it's a bit difficult to see what is going on, so I'll add some colour and help things a bit. Specifically, I'm going to colour a term that is within brackets that needs to be done before we can so the division (which is the operation that jumped out at me at first!):

So I'm going to do the green section separately, then put the result back in:

and now let's put the solution to this part back into the original:

and now we can take the absolute value:

#### Explanation:

The | | turns what ever is inside it into a positive value.

AS an example:

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Bracket within brackets is called nested brackets. In this situation you consider each pair of brackets working outwards

Step 1:

Step 2:

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