How do you simplify and find the excluded value of (2b )/ (6b-2)?

Jun 16, 2017

$\frac{b}{3 b - 1}$

Explanation:

$\text{factorise the denominator by taking out 2 as a }$
$\textcolor{b l u e}{\text{common factor}}$

$\Rightarrow \frac{2 b}{2 \left(3 b - 1\right)}$

$= \frac{{\cancel{2}}^{1} b}{{\cancel{2}}^{1} \left(3 b - 1\right)} \leftarrow \text{ cancelling}$

$\text{excluded values are any values of b that make the }$
$\text{denominator equal to zero as this would make the}$
$\text{fraction "color(blue)"undefined}$

$\Rightarrow \text{solve } 3 b - 1 = 0 \Rightarrow b = \frac{1}{3}$

$\Rightarrow b = \frac{1}{3} \text{ is the excluded value}$