How do you simplify and find the excluded value of #(3x^2 - 3) /( 6x - 6 )#?

1 Answer
May 24, 2016

Answer:

excluded value is x = 1 for unsimplified expression
no excluded value for simplified expression
simplified: #(x + 1)/2#

Explanation:

factor numerator: #3(x^2 - 1)# = #3(x - 1)(x + 1)#
factor denominator: #6(x - 1)#
#(3(x-1)(x+1))/(6(x-1))# which simplifies to #(x +1)/2#
to find excluded value set denominator = 0 and solve for variable to find excluded value. Since cannot divide by 0, any value of the variable that makes the denominator = 0 is excluded
#6(x - 1) = 0# #-> (x - 1) = 0 -> x = 1#