How do you simplify and find the excluded value of #(4x-12)/(4x)#?

1 Answer
May 29, 2017

Answer:

See a solution process below:

Explanation:

First, this expression can be rewritten as:

#(4x)/(4x) - 12/(4x) => color(red)(cancel(color(black)(4x)))/color(red)(cancel(color(black)(4x))) - 12/(4x) => 1 - 12/(4x) =>#

#1 - (4 xx 3)/(4x) => 1 - (color(red)(cancel(color(black)(4))) xx 3)/(color(red)(cancel(color(black)(4)))x) => 1 - 3/x#

Because you cannot divide by #0# the excluded value is:

#4x != 0# or #x != 0#