How do you simplify and find the excluded values of #(16x^2 - 4x)/(3 - x)#?

2 Answers
Feb 5, 2018

Let's try factoring everything

#(4x(4x-1))/(3-x)#

It looks like there are no common factors here, so we can't simplify it

However, there are still excluded values. These are any values of #x# that make the denominator #0# (we can't have that, because that would be dividing by #0#).

So let's set #3-x# equal to #0# and solve for #x#

#3-x = 0#

#-x=-3#

#x=3#

So the excluded value for this expression is #x=3#

Feb 5, 2018

Answer:

#(4x(4x-1))/(3-x)to(x!=3)#

Explanation:

#"factorise numerator by taking out a "color(blue)"common factor of 4x"#

#=(4x(4x-1))/(3-x)#

#"the denominator cannot equal zero as this would make"#
#"the rational function undefined. Equating the "#
#"denominator to zero and solving gives the value that x "#
#"cannot be"#

#"solve "3-x=0rArrx=3larrcolor(red)"excluded value"#