How do you simplify and find the excluded values of #(3x-6)/(x-2)#?

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Answer 1 · 2017-01-18T15:08:49

See the entire simplification process below:

First, to simplify this expression we can rewrite the numerator as follows:

#(3x - 6)/(x - 2) -> ((3 xx x) - (3 xx 2))/(x - 2) -> (3(x - 2))/(x - 2)#

We can now cancel terms to simplify the expression:

#(3color(red)(cancel(color(black)((x - 2)))))/color(red)(cancel(color(black)((x - 2)))) -> 3#

We need to exclude values where the numerator is #0#:

#x - 2 = 0#

#x - 2 + color(red)(2) = 0 + color(red)(2)#

#x - 0 = 2#

#x = 2#

This expression simplifies to #3# except where #x = 2#.