How do you simplify and find the restrictions for #(3b)/(b(b + 9))#?

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Answer 1 · 2017-04-27T12:38:24

See the solution process below:

To simplify this expression cancel the common term in the numerator and denominator:

#(3b)/(b(b + 9)) = (3color(red)(cancel(color(black)(b))))/(color(red)(cancel(color(black)(b)))(b + 9)) = 3/(b + 9)#

To find the restrictions we need to use the original form of the expression. Because we cannot divide by #0# we must solve for:

#b(b + 9) = 0#

To solve this we solve each term for 0:

1)

#b = 0#

2)

#b + 9 = 0#

#b + 9 - color(red)(9) = 0 - color(red)(9)#

#b + 0 = -9#

#b = -9#

The restrictions are:

#b != 0# and #b != -9#