How do you simplify and restricted value of #5/(7z+5)#?

1 Answer
Jim G.
Oct 10, 2017

#z!=-5/7#

Explanation:

#"since neither the numerator nor denominator can be"#
#"factored then fraction is described in simplest form"#

#rArr5/(7z+5)larrcolor(blue)" is in simplest form"#

The denominator cannot be zero as this would make the fraction undefined. Equating the denominator to zero and solving gives the value that z cannot be.

#"solve "7z+5=0rArrz=-5/7larrcolor(red)" restricted value"#

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