How do you simplify and state the excluded values for #(3x) /( 1-3x)#?

2 Answers
Jul 27, 2015

Answer:

I am afraid there is not much to simplify.

Explanation:

The excluded value for #x# is when #1-3x=0=>x!=1/3#

because you may not divide by #0#.

Jul 27, 2015

Answer:

Excluded value : #x=1/3#

Explanation:

Add and subtract #(1)# from the numerator to get from #" "(3x)/(1-3x)" "# to this : #(1+3x-1)/(1-3x)" "#

then to #" "(3x-1)/(1-3x) +1/(1-3x)#

Which could also be written as : #(-1*(3x-1))/((3x-1))+1/(1-3x)color(red)= color(blue)(1/(1-3x)-1)#

Now, we can see that if #(1-3x)=0# the expression would be undefined in #RR#

So, we say that the excluded values of #x# are those for which #(1-3x)=0#

#=>3x=1=>color(blue)(x=1/3) " "# is the excluded value.