# How do you simplify and write (4w^-6x^2)^2 with positive exponents?

First of all, let's remove that big squared symbol around the whole equation. Note: You will need to know two things, ${\left(a b\right)}^{n} = {a}^{n} \cdot {b}^{n}$, and ${\left({a}^{m}\right)}^{n} = {a}^{m n}$
${\left(4 \cdot {w}^{-} 6 \cdot {x}^{2}\right)}^{2} = {4}^{2} \cdot {w}^{- 6 \cdot 2} \cdot {x}^{2 \cdot 2}$
$= 16 \cdot {w}^{- 12} \cdot {x}^{4}$
But the question asks for all exponents (those smaller, higher numbers) to be positive. For this we need another piece of knowledge: ${a}^{-} n = \frac{1}{a} ^ n$
$= \frac{16 \cdot {w}^{4}}{x} ^ 12$