# How do you simplify  (b^2 *- 3b^3a^-1)3n^0b^-2?

May 25, 2018

$- 9 \cdot {b}^{3} / a$

#### Explanation:

${n}^{0} = 1$ if $n \setminus \ne 0$
then we have
$- 9 {b}^{5} \cdot {b}^{-} 2 \cdot {a}^{-} 1$
This is equivalent to
$- 9 \cdot {b}^{3} / a$
for $a \setminus \ne 0$