Question

How do you simplify `(b^4c^6f^8)/(b^4c^3f^5)`?

Answer 1

`c^3f^3`

Explanation:

Remember that `x^a/x^b=x^(a-b)`.

We use this for like terms (so the `b`s together, the `c`s, and the `f`s)

This becomes:

`(b^4c^6f^8)/(b^4c^3f^5)=b^(4-4)c^(6-3)f^(8-5)=c^3f^3`