How do you simplify # (bc)/(pia) + (ac)/(pib) + (ab)/(pi*c)#?

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Answer 1 · 2018-03-28T20:39:28

#(b^2c^2+a^2c^2+a^2b^2)/(pi*abc)#

#(bc)/(pi*a) + (ac)/(pi*b) + (ab)/(pi*c)#
#=(b^2c^2)/(pi*abc) + (a^2c^2)/(pi*abc) + (a^2b^2)/(pi*abc)#
#=(b^2c^2+a^2c^2+a^2b^2)/(pi*abc)#

How do you simplify # (bc)/(pi*a) + (ac)/(pi*b) + (ab)/(pi*c)#?