How do you simplify #(c^7d^3)/(c^3d^5)#?

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Answer 1 · 2016-12-23T13:24:50

#c^4d^-2# or #c^4/d^2#

To simplify this there are two rules of exponents we can use:

#color(red)(x^a/x^b = x^(a-b))#

and

#color(red)(x^a/x^b = 1/x^(b-a))#

So we can simplify this expression in one of two ways:

First simplification:

#(c^7d^3)/(c^3d^5) -> c^(7-3)d^(3-5) -> c^4d^-2#

Second simplification:

#(c^7d^3)/(c^3d^5) -> c^(7-3)/d^(5-3) -> c^4/d^2#