How do you simplify #(c/a+c/b) / (c/(ab))#? Algebra Rational Equations and Functions Division of Rational Expressions 1 Answer Alan P. Sep 28, 2015 #a+b# Explanation: [1]#color(white)("XXX")color(blue)((c/a+c/b) = (bc+ac)/(ab) = (c(a+b))/(ab))# [2]#color(white)("XXX")color(blue)((c/a+c/b))/color(red)((c/(ab))) = color(blue)((c/a+c/b))*color(red)(((ab)/c))# Substituting result [1] into [2] #color(white)("XXX")color(blue)((c/a+c/b))/color(red)((c/(ab))) = color(blue)((c(a+b))/(ab))*color(red)((ab)/c)# #color(white)("XXX")(c/a+c/b)/(c/(ab)) = (cancel(c)(a+b))/(cancel(ab))*(cancel(ab))/cancel(c) = a+b# Answer link Related questions What is Division of Rational Expressions? How does the division of rational expressions differ from the multiplication of rational expressions? How do you divide 3 rational expressions? How do you divide rational expressions? How do you divide and simplify #\frac{9x^2-4}{2x-2} -: \frac{21x^2-2x-8}{1} #? How do you divide and reduce the expression to the lowest terms #2xy \-: \frac{2x^2}{y}#? How do you divide #\frac{x^2-25}{x+3} \-: (x-5)#? How do you divide #\frac{a^2+2ab+b^2}{ab^2-a^2b} \-: (a+b)#? How do you simplify #(w^2+6w+5)/(w+5)#? How do you simplify #(x^4-256)/(x-4)#? See all questions in Division of Rational Expressions Impact of this question 1489 views around the world You can reuse this answer Creative Commons License