# How do you simplify completely (12x^3-4x^2+8x)/(-2x)?

Provided $x \ne 0$
$\frac{12 {x}^{3} - 4 {x}^{2} + 8 x}{- 2 x}$
$= \frac{12 {x}^{3}}{- 2 x} + \frac{- 4 {x}^{2}}{- 2 x} + \frac{8 x}{- 2 x}$
$= - 6 {x}^{2} + 2 x - 4$