Question

How do you simplify `cos(2pi/3)cos(pi/6)+sin(2pi/3)cos(pi/6)`?

Answer 1

`=>1/4(3-sqrt3)`

Explanation:

`cos(2pi/3)cos(pi/6)+sin(2pi/3)cos(pi/6)`

`=>cos(pi-pi/3)cos(pi/6)+sin(pi-pi/3)cos(pi/6)`

`=>-cos(pi/3)cos(pi/6)+sin(pi/3)cos(pi/6)`

`=>(-1/2*sqrt3/2)+(sqrt3/2*sqrt3/2)`

`=>1/4(3-sqrt3)`