How do you simplify #cos ( pi - a ) + sin ( (pi/2) + a)#?

1 Answer
Jun 4, 2016

0

Explanation:

Using the following #color(blue)"Addition formulae"#

#color(red)(|bar(ul(color(white)(a/a)color(black)(cos(A±B)=cosAcosB∓sinAsinB)color(white)(a/a)|)))#

#color(red)(|bar(ul(color(white)(a/a)color(black)(sin(A±B)=sinAcosB±cosAsinB)color(white)(a/a)|)))#

#rArrcos(pi-a)+sin(pi/2+a)#
#"------------------------------------------------"#

#cos(pi-a)=cos(pi)cosa+sin(pi)sina=-cosa#

#sin((pi/2)+a)=sin(pi/2)cosa+cos(pi/2)sina=cosa#
#"---------------------------------------------------"#

adding these 2 results together.

#rArrcos(pi-a)+sin((pi/2)+a)=-cosa+cosa=0#