How do you simplify #(d^2-16)/( d+4)#?

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Answer 1 · 2018-04-04T10:53:15

#d-4 #

Use the difference in two squares:

#a^2-b^2 = (a+b)(a-b) #

#=> d^2 - 16 = (d)^2 - ( 4)^2 #

#=> (d-4)(d+4) #

#=>( (d-4)(d+4))/(d+4) #

Cancel out...

#=>( (d-4)cancel((d+4)))/cancel(d+4) #

#color(blue)( = d-4 #