How do you simplify #e^lnx#?

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Bdub Share
Mar 22, 2016

Answer:

#e^lnx=x#

Explanation:

let # y=e^lnx#
#ln y=lne^lnx#->Take ln of both sides
#lny = lnx * ln e# -> use the property #log_b x^n = nlog_b x#
#lny=lnx(1)#-> #ln_e e = 1#-> from the property #log_b b = 1#
#lny = ln x#
Therefore #y=x#

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