How do you simplify #\frac { 40x ^ { 2} - 27x - 7} { 5x + 1}#?

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Answer 1 · 2018-01-21T04:44:59

#(40x^2-27x-7)/(5x+1)=8x-7#

#(40x^2-27x-7)/(5x+1)#

= #(40x^2-35x+8x-7)/(5x+1)#

= #(5x(8x-7)+1(8x-7))/(5x+1)#

= #((5x+1)(8x-7))/(5x+1)#

= #8x-7#

Answer 2 · 2018-01-21T04:55:24

#:. x = 7/8#

Use Trinomial Factoring on the Numerator:

= #(8x-7)(5x+1) // (5x+1)#

Divide Out Like Terms or Simply Cross Them Out:

= #(8x-7)(cancel(5x+1)) // (cancel(5x+1))#

Isolate for #x#:

= #(8x-7)#

#:. x = 7/8#