Question

How do you simplify `\frac { 4a b c } { 2c ^ { 2} }`?

Answer 1

See a solution process below:

Explanation:

First, simplify the constants as:

`(4abc)/(2c^2) = ((2 xx 2)abc)/(2c^2) = ((color(red)(cancel(color(black)(2))) xx 2)abc)/(color(red)(cancel(color(black)(2)))c^2) =`

`(2abc)/c^2`

Now, use these rules of exponents to simplify the `c` term:

`a = a^color(red)(1)` and `x^color(red)(a)/x^color(blue)(b) = 1/x^(color(blue)(b)-color(red)(a))` and `a^color(red)(1) = a`

`(2abc)/c^2 = (2abc^color(red)(1))/c^color(blue)(2) = (2ab)/c^(color(blue)(2)-color(red)(1)) = (2ab)/c^1 = (2ab)/c`