Question

How do you simplify `\frac { 4y ^ { 2} } { x ^ { 0} y ^ { 3} }`?

Answer 1

See a solution process below:

Explanation:

First, use this rule of exponents to simplify the `x` term:

`a^color(red)(0) = 1`

`(4y^2)/(x^color(red)(0)y^3) => (4y^2)/(1 * y^3) => (4y^2)/y^3`

Next, use these rule of exponents to simplify the `y` term:

`x^color(red)(a)/x^color(blue)(b) = 1/x^(color(blue)(b)-color(red)(a))` and `a^color(red)(1) = a`

`(4y^color(red)(2))/y^color(blue)(3) => 4/y^(color(blue)(3)-color(red)(2)) => 4/y^color(red)(1) => 4/y`

Answer 2

It becomes `4/y`

Explanation:

First of all, anything raised to the zero power is going to be 1, so that `x^0` just is one, and won't affect the problem. Second of all, you can cancel out exponents when working with fractions, so the `y^2/y^3` will become `1/y^1` and you can simplify that to just `1/y`. We can't forget the 4 either, so in all actuality, your expression simplifies to `(4*1)/y` or just `4/y`