How do you simplify #\frac { 65x ^ { 2} x ^ { 11} y ^ { 5} y ^ { 9} } { 5x x ^ { 3} y ^ { 2} x ^ { 2} }#?

1 Answer
Mar 24, 2018

Answer:

#13x^7y^2#

Explanation:

#(65x^2x^11y^5y^9)/(5x x^3y^2x^2) rarr# Combine all the like terms in the numerator and the denominator first

#(65x^(2+11)y^(5+9))/(5x^(1+3+2)y^2)#

#(65x^13y^14)/(5x^6y^2)#

65 is evenly divisible by 5

#(13x^13y^14)/(x^6y^2) rarr# Exponents can be subtracted from each other when dividing (ex. #x^6/x^2=x^(6-2)=x^4#)

#13x^(13-6)y^(14-2)#

#13x^7y^2#