Question

How do you simplify `\frac { 8x - 8} { x ^ { 2} - 4} = \frac { 4} { x - 2}`?

Answer 1

`((8x - 8)(x - 2))/(x^2 - 4) = 4`

`((8x - 8)(x- 2))/((x + 2)(x - 2)) = 4`

`8x - 8 = 4(x + 2)`

`8x - 8 = 4x + 8`

`4x = 16`

`x = 4, x!= +-2`

Hopefully this helps!