How do you simplify (\frac { u ^ { 3} v ^ { - 1} } { 2w ^ { 3} } ) ^ { - 3} ( u w ^ { 3} )?

1 Answer
Mar 27, 2017

(8v^3w^12)/u^8

Explanation:

Since (a^b)^c=a^(bc), you get:

(u^-9v^3)/(2^-3w^-9)*uw^3;

since a^b*a^c=a^(b+c), you get:

(u^-8v^3w^3)/(2^-3w^-9);

since a^b/a^c=a^(b-c), you get:

(u^-8v^3w^12)/2^-3;

since a^-b=1/a^b, you get:

(2^3v^3w^12)/u^8

=(8v^3w^12)/u^8