How do you simplify (\frac { z ^ { 3} } { 2y ^ { 4} } ) ^ { 3}(z32y4)3?

1 Answer
Feb 21, 2017

z^9/(8y^12)z98y12

Explanation:

(x^3/(2y^4))^3=z^(3(3))/(2^3y^(4(3)))=z^9/(8y^12)(x32y4)3=z3(3)23y4(3)=z98y12

don't get confused between these two exponent rules
(x^a)^b=x^((a)(b))(xa)b=x(a)(b)
(x^a)*(x^a)=x^(a+a)(xa)(xa)=xa+a