How do you simplify #(g^2/h)/(g^5/h^2)#?

1 Answer
Mar 19, 2017

Answer:

#((g^2)/h)/((g^5)/(h^2))=color(green)(h/(g^3))#

Explanation:

Division is equivalent to multiplication by the (multiplicative) inverse.

So #((g^2)/h)/((g^5)/(h^2))#

is equivalent to #((g^2)/h) xx((h^2)/(g^5))#

#color(white)("XXX")(color(red)(cancel(color(black)(g^2)))/(color(blue)(cancel(color(black)(h)))))xx(color(blue)(cancel(color(black)(h^2))^h)/(color(red)(cancel(color(black)(g^5))_(g^3))))#

#color(white)("XXX")=h/(g^3)#