How do you simplify #h(x)= log (x^2+6x+9)(sqrt(x^2-1))#?

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Answer 1 · 2018-04-05T11:17:47

#2log(x+3)+1/2log(x^2-1)#

Factor: #x^2+6x+9#

#(x+3)^2#

#sqrt(x^2-1)=(x^2-1)^(1/2)#

#:.#

#log(x+3)^2(x^2-1)^(1/2)#

#->log(x+3)^2+log(x^2-1)^(1/2)#

#->2log(x+3)+1/2log(x^2-1)#

This is as far as I can go.